Find number ab, where a is the tens' digit and b is the units’ digit, knowing that a4 + a2 = 5 · b.
Solution:
The problem requires us to find a two digit number ab, where a is the tens digit and b is the units’ digit.
The problem requires us to find a two digit number ab, where a is the tens digit and b is the units’ digit.
Figures may have values from 1 to 9 (for a=0 result 04 + 02 = 5 · b => b=0, and the number ab=0 is not a two-digit number).
From a4 + a2 = 5 · b. We note that 5b is a multiple of 5.
a4 + a2 = a2 (a2 +1) must be multiple of 5.
a2 can’t be 5 (a is a natural number)
a2 +1 = 5;
a2 = 5-1 = 4;
a = 2
4*5 = 5 *b
b = 4
Other case, for the next multiple of 5
a2 +1=10
a2=9
a=3
a2(a2+1) = 9*10
= 90 = 5*b =>b = 90/5 = 18 >9, impossible, b is a digit, b< 9
The only number ab that is solution to the problem is 24.
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